Question

A wire is 7x−3meters long. A length of 3x−4meters is cut for use.a)How much wire is left?b)If this left out wire is used for making an equilateral triangle, what is the length of each side of the triangle so formed?

Answer 1

Answer:

Step-by-step explanation: answer is

7x-3 -(3x-4)

= 4x+1

For triangle,

4x+1 ÷ 3

Answer 2

$\large{\underline{\rm{\red{\bf{Question:-}}}}}$

A wire is $\rm 7x-3$ meters long. A length of $\rm 3x-4$ meters is cut for use.

a) How much wire is left?

b) If this left out wire is used for making an equilateral triangle, what is the length of the each side of the triangle so formed?

$\large{\underline{\rm{\red{\bf{Given:-}}}}}$

Total length of the wire = $\sf 7x-3 \: m$

Length of the wire that is cut = $\rm 3x-4 \: m$

$\large{\underline{\rm{\red{\bf{To \: Find:-}}}}}$

The length of wire that is left.

If this left out wire is used for making an equilateral triangle, find the length of each side of the triangle so formed.

$\large{\underline{\rm{\red{\bf{Solution:-}}}}}$

Given that,

Total length of the wire = $\sf 7x-3 \: m$

Length of the wire that is cut = $\rm 3x-4 \: m$

Then,

Length of the wire left = Total length of wire − Length of the wire that is cut

Length of the wire left = $\sf (7x-3)-(3x-4)$

$\sf = 7x-3-3x-4$

$\sf = \underline{\underline{(4x+1) \: m}}$

Now,

Perimeter of an equilateral triangle = $\sf (4x+1) \: m$

$\boxed{\sf 3s=(4x+1)}$

[ S = Each side of the triangle ]

$\longrightarrow \sf S = \bigg( \dfrac{4x+1}{3} \bigg) \: m$

Therefore,

Length of each side of an equilateral triangle = $\sf S = \bigg( \dfrac{4x+1}{3} \bigg) \: m$