Question

a wire is(9×-5) meter long a length of (2×+2) meter is cot out of it for use how much wire is left​

Answer 1

Solution

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Given,

length of wire =(7x−3)m

and wire cut for use has length =(3x−4)m

Left wire =(7x−3)−(3x−4)=(4x+1)m

(b) Left wire =(4x+1)m

Perimeter of equilateral triangle = Length of wire left

⇒ 3×side=4x+1

⇒ side=3(4x+1)​=31​(4x+1)m

Answer 2

Answer:

length=5m=l

ϕ=30°

30× 180π

= 6π rad

lθ=r×ϕ

5(θ)=10 −3 ( 6π )

θ=10 −3 ( 30π )=10 −1( 33.14 )rad

=(1.04667)×10 −4 ×( π180 )

=59.9697×10 −4 ×60min

=0.3598sec≈0.36

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