Question

A wire is bent in a circle of radius 10cm it is given a charge of 250 microcoulomb which spreads on it uniformly. What is the electric potential and intensity of field at its centre?

Answer 1

electric potential is given by
$V=\frac{1}{4pieE} * \frac{q}{r}$
$V=9* 10^{9} * \frac{250* 10^{-6} }{ 10^{-1} }$
$V=2250* 10^{4}$
$V=2.250* 10^{7}$

Answer 2

Given:

radius  = 10cm

charge = 250 microcoulomb

To Find:

electric potential (V)

Solution:

we know,

Electric field intensity at the center of a uniformly charged object is zero.

also

the electric potential at the center is given by

V = kQ / r

V = 9 * 10⁹ *( 250 * 10⁻⁶) / 10⁻¹    {since, k =9 * 10⁹ }

V = 2250 * 10⁴

V = 2.250 * 10⁷ volt

So, the electric potential is 2.250 * 10⁷ volt, and the intensity of field = 0.