A wire is bent in a form of square encloses an area of 5929 cm².find the area enclosed, if the same wire is bent to form a circle.
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Answer:
≅7549.03
Step-by-step explanation:
s = side of the square
s² = 5929 ⇒ a = √5929 = 77
total length of the wire = perimete of the square = 4×s = 4×77 = 308
perimete of the new circle = 308
The formula for perimete of a circle = 2×π×r
r = Radius π ≅ 3.1415926536
2×π×r = 308 ⇒ r ≅ 49.0197224723
The formula for area of a circle = π×r²
Area of circle= π×r² =3.1415926536 × (49.0197224723)² =7549.0372607348
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