Question

A wire is bent in form of equilateral
triangle [Area =S cm^2] . then the
same wire is bent in form a circle. Find the area of circle
​

Answer 1

Answer:

let the side of triangle is a

(√3/4)a^2 = A

a = √ 4*A / √3

a = 2 √ A/ √3

3a = 6√A/ √3

perimeter of triangle = circumference of circle

6√A/ √3 = 2 *π* r

r = 3√ A / √3 π

r = √3 *√ A / π

area = π *r*r

area = π * (√3*√ A / π) * (√3* √A/ π)

area = 3A / π = 21 A/22

Step-by-step explanation:

hope you got ur answer plzz brainliest my answer