Question

A wire is bent in the form of a circular arc with a straight portion AB magnetic induction at O when current I is flowing in the wire is ?

Answer 1

Answer:

Correct option is

C

2πr

μ

0

I

(π−θ+tanθ)

B=

4π(OC)

μ

0

I

[2sinθ]

But OC=rcosθorB

AB

=

2π

μ

0

I

tanθ

Magnetic field due to circular portion,

B

AB

=

2r

μ

0

I

(

2π

2π−2θ

)=

2r

μ

0

I

(π−θ)

Total magnetic field

=

2π

μ

0

I

tanθ+

2r

μ

0

I

(π−θ)=

2πr

μ

0

I

[tanθ+π−θ]