Question

A wire is bent in the form of a regular hexagon of side 22/3 CM if the same wire is bent to form a regular pentagon what will be the length of each side

Answer 1

Answer:

$\red { Length \: of \: side \: of \: regular \: pentagon }$

$\green { = \frac{44}{5} \:cm}$

Step-by-step explanation:

$Let \: x\:cm \: and \: y \:cm\: are \: sides \: of \\ Pentagon \: and \: Hexagon \: respectively$

$y =\\frac{22}{3} \:cm\: (given)$

/* According to the problem given,

If Same wire is bent to form a regular pentagon then

$Perimeter \: of \: the \: Pentagon = Perimeter \: of \: the \: Hexagon$

$\implies 5x = 6y$

$\implies 5x = 6 \times \frac{22}{3}$

$\implies 5x = 44$

$\implies x = \frac{44}{5} \:cm$

Therefore.,

$\red { Length \: of \: side \: of \: regular \: pentagon }$

$\green { = \frac{44}{5} \:cm}$

•••♪

Answer 2

Step-by-step explanation:

Letxcmandycmaresidesof

PentagonandHexagonrespectively

\begin{gathered} y =\\frac{22}{3} \:cm\: (given) \end{gathered}

y=

frac223cm(given)

/* According to the problem given,

If Same wire is bent to form a regular pentagon then

Perimeter \: of \: the \: Pentagon = Perimeter \: of \: the \: HexagonPerimeterofthePentagon=PerimeteroftheHexagon

\implies 5x = 6y⟹5x=6y

\implies 5x = 6 \times \frac{22}{3}⟹5x=6×

3

22

\implies 5x = 44⟹5x=44

\implies x = \frac{44}{5} \:cm⟹x=

5

44

cm

Therefore.,

\red { Length \: of \: side \: of \: regular \: pentagon }Lengthofsideofregularpentagon

\green { = \frac{44}{5} \:cm}=

5

44

cm