Question

A wire is bent in the form of a regular hexagone of side 24 cm. the same
wire is rebind in the form of a regular octagone. What will be the side of this
octagone?

Answer 1

Answer:

18cm

Step-by-step explanation:

Given that hexagon has a side of 24cm. So, we can find the perimeter of their hexagon from the given info.

We know that the sum of all sides in the perimeter. A hexagon has six sides. If one side an of 24cm, 6 sides will be 24 × 6 = 144cm

Perimeter or the length of the wire = 144cm

Now, the same wire is used to make an octagon. An octagon has eight sides.

Perimeter = Sum of all sides

Length of each side = perimeter of the wire/no of sides

Length of each side = 144/8 = 18cm

hence, the sum of each side of the octagon with a perimeter of 144cm is 18cm.

Answer 2

Question:-

• A wire is bent in the form of a regular hexagone of side 24 cm. the same wire is rebind in the form of a regular octagone. What will be the side of this octagone?

Given:-

• A wire is bent in the form of a regular hexagon of size 24 cm.
• The same wire is bent into a form of regular octagon.

To Find:-

• Find the size of octagon.

Solution:-

Here ,

The perimeter of hexagon is

$\tt\implies \: 24 \times 6$

144 cm

• Perimeter of wire is 144 cm

Now ,

Octagon has 8 side so ,

$\tt\implies \: Length \: \: of \: \: each \: \: side = \dfrac { Perimeter \: \: of \: \: wire } { Number \: \: of \: \: sides }$

$\tt\implies \: Length \: \: of \: \: each \: \: side = \dfrac { 144 } { 8 }$

$\tt\implies \: Length \: \: of \: \: each \: \: side = 18 cm$

Hence ,

• Length of each side is 18 cm.