Question

A wire is bent in the form of a square in close an area 400 cm² . The same wire is been been in the form of a circle find the area enclosed by the circle.

Answer 1

let the side of square be x

we know, area of square=

${side}^{2}$

$therefore \: 400 = {s}^{2} \\ \sqrt{ {400}^{2} } = \sqrt{ {s}^{2} } \\ 20 = s$

We can say that side of area=diameter of circle

therefore,

$\frac{20}{2} = radius \\ 10 = radius$

Now Area of Circle,

$= \pi {r}^{2} \\ = 3.14 \times {(10)}^{2} \\ = 3.14 \times 10 \times 10 \\ = 314 {cm}^{2}$

therefore, Area= 314cm^2