Question

a wire is bent in the form of a square occupies an area of 196m. if the same wire is bent to form a circle, find the area occupies.

Answer 1

the area of circle will be equal to the area of square
so
perimeter of square =circumference of circle

area of square=196m
s*s=196
s^2=196
s=14m
perimeter of square =4*side=4*14=56m
perimeter of square=circumference of circle
56m=56m

circumference of circle=56m
2πr=56

44/7*r=56

r=56*7/44
r=28*7/22=14*7/11
r=98/11m

area of circle will be πr^2
22/7*98/11*98/11=30184


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Answer 2

Let the side of square be a m
According to question
a^2 = 196
a=14
Perimeter of square =14*4=56
Circumference of circle =56
2 pi *r =56
r=28/pi

Area of circle = pi * r*r
= pi *28*28/pi *pi
= 28*28*7/22
=5488/22
= 249.46