Question

a wire is bent in the form of a square of area 1936 CM square if the same wire is bent to form a circle find the radius of the circle and the area enclosed​

Answer 1

Answer:

Radius of circle = 28 cm, the area enclosed = 2464 $cm^{2}$

Step-by-step explanation:

   Given a wire is bent in the form of square

                           area of square $a^{2}$ = 1936 $cm^{2}$  ( a is side of square )

                                                    $a^{2}$ = 44 × 44   ( $\sqrt{1936}$ = 44 )

                                                    $a = 44$ cm

     perimeter of square = 4$a$ = 4 × 44 = 176 cm

     here perimeter of square is the length of wire

     the same wire is bent to form circle,

      ∴ the perimeter of circle = length of wire

                                      $2\pi r =$ 176

                                   $2 [ \frac{22}{7} ] r = 176$    

                                     r = $[\frac{176}{2} ]$×$[\frac{7}{22} ]$

                                    r =  $\frac{1232}{44}$=28 cm

       ∴ area of the circle = $\pi r^{2}$= $[\frac{22}{7}]$ ×28×28

                                                22×4×28 =2464 $cm^{2}$