Question

A wire is bent in the form of a square whose each side is 14 cm .If it is rebent in the form of a rectangle of 10 cm wide,find the length of the rectangle ​

Answer 1

Answer:

18

Step-by-step explanation:

perimeter of the square equals to 4 *side

So 4*14= 56

since the square is bent into rectangle perimeters of both are same

perimetre of rectangle = 2(l + b)= 56

l+b= 28

l+10= 28

length= 18

Answer 2

Answer:

Perimeter of the square = 4×side

= 4×14

=56

Perimeter of the rectangle = 2(L+B)

=2(L+ 10)

As we know

Area of rectangle = area of square

56 = 2(L+10)

56÷2 = L +10

28 - 10 = L

18 =L