A wire is bent in the form of a triangle. If the lengths of the sides of the triangle of the triangle are (7x2 −5x) cm, ( 3x+ 4x2 )cm and ( 8x−4) cm , find the length of the wire.
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Answer:
Step-by-step explanation:
Sides of triangle are 5x+2,5x and 3x−5
As x>0 so the longest side or the hypotenuse is 5x+2
Using pythagoras theorem
(3x−1)
2
+(5x)
2
=(5x+2)
2
⇒9x
2
+1−6x+25x
2
=25x
2
+4+20x
⇒9x
2
−26x−3=0
⇒9x
2
−27x+x−3=0
⇒9x(x−3)+1(x−3)=0
⇒(9x+1)(x−3)=0
⇒x=−
9
1
,3
But x>0
⇒x=3
So the sides are
5x+2=15+2=17
5x=15
3x−1=9−1=8
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