Question

a wire is bent in the shape of a rectangle . it's length is 36cm and breadth is 25cm . if the same wire is bent in the shape of a square , what will be the measure of its side?among these two shape which shape occupies more area??

Answer 1

A wire is bent in the shape of a rectangle . it's length is 36cm and breadth is 25cm

so perimeter of it
⇒2(l+b)
⇒2(36+25)
⇒2(61)
⇒122 cm

now tthe same wire is bent in form of square
so perimeter is 122cm
side= 122/4[perimeter of square=4s]
side =30.5cm
the measure of side of square is 30.5cm

area of retcangle=l*b                                area of square=side*side
⇒36*25                                                     ⇒30.5²
⇒900                                                            ⇒930.25
hence square has more area

hope it helps
MATHS ARYABHATTA
OMKARA2

Answer 2

perimeter of rectangle = 2(length+breadth)

perimeter of rectangle = 2(36+25)

perimeter of rectangle = 2*61

perimeter of rectangle = 122 cm

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perimeter of square = perimeter of rectangle 

perimeter of square = 122 cm

4*side= 122

side = 122/4

side = 30.5

length of side of square = 30.5 cm

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Now,

area of rectangle = length*breadth 

area of rectangle = 36*25

area of rectangle = 900 cm^2



area of square = side^2

area of square = 30.5^2

area of square = 930.25 cm^2


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among them, square occupies more area that rectangle 

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i hope this will help you




-by ABHAY, MATHS ARYABHATTA