Question

A wire is bent in the shape of a rectangle. Its length is 36cm and breadth is 25 cm. If the same wire is bent in the shape of a square, what will be the measure of its side? Among these two shape wch shape occupies more area?

Answer 1

perimeter of rectangle = 2*(36+25) = 122

Let side of square = a cm

Perimeter of square = Perimeter of rectangle

4*a = 122

a = 30.5 cm

Now area of rectangle = 36*25 = 900

Area of square = (30.5)*(30.5)= 930.25

Therefore ,

area of square > area of rectangle

Answer 2

perimeter of rectangle=length of the total wire
perimeter of rectangle=2(l+b)
= 2(36+25)
=2(61)
=122cm
length of the wire=perimeter of rectangle=perimeter of square
perimeter of square=perimeter of rectangle
perimeter of square=4s=122cm
side=122/4
=30.5
area occupied by rectangle=l×b
=36×25
=900
area occupied by square=s×s
=30.5×30.5
=930.25
thus, square occupies more area.