Question

A wire is bent in the shape of a rectangle. Its length is 45 m and breadth is 25 m. If the same wine ja
rebent in the shape of a square, what will be the measure of each side? Also find which shape enclose
more area, rectangle or square?​

Answer 1

Question ⤵

A wire is bent in the shape of a rectangle. Its length is 45 m and breadth is 25 m. If the same wine ja

rebent in the shape of a square, what will be the measure of each side? Also find which shape enclose

more area, rectangle or square?

Solution ⤵

For Rectangle ⤵

Lenght => 45 m

Breadth => 25m

Perimeter of Rectangle => 2 ( l+b)

=> 2 (45+25)

=> 2× 70

=> 140m

For Square ⤵

Perimeter of Rectangle = Perimeter of Square

140m = 4x

x = 140/4

x = 35 m

Side Of Square is 35 metre.

Answer 2

Answer:

According to the question:-

Perimeter of rectangle=Perimeter of square

$\bold{ \implies{4 \times side = 2(length + breadth)}}$

$\bold{\implies 4 \times side = 2(45m + 25m)}$

$\bold{ \implies{4 \times side = 2 \times 70m}}$

$\bold{ \implies{side = \frac{2 \times 70}{4} = 35cm}}$

Thus, the side of the square is 35 cm.

$\bold{Now \: the \: area \: of \: rectangle=l×b}$

$\bold {\implies{45 \times 25 = {990}cm^{2} }}$

$\bold{ \implies{Area \: of \: square = side \times side}}$

$\bold{ \implies{35 \times 35 = 1225 {cm}^{2} }}$

Therefore on comparing the area of square is greater than the rectangle.