Question

A wire is bent in the shape of a rectangle of sides 20cm and 16cm if it is bent in the shape of a square then what will be the length of the square​

Answer 1

Length of wire  =  Perimeter of the rectangle = 2(20+16) cm = 72 cm

Perimeter of square = Length of wire = 72 cm

Side of square = Perimeter/4 = 72/4 cm = 18 cm

Answer 2

Answer:

The Side of the Square is 18 cm.

Step-by-step explanation:

Given :

Dimensions of the rectangle = 20 cm × 16 cm

It is remoulded into a = square

To find :

The measure of the square's side

Solution :

As the shape is remoulded, the perimeter of both Rectangle and Square would be the same.

★ $\textsf{\underline{\underline{Perimeter of the rectangle -}}}$

$\boxed{\sf{2(Length + Breadth)}}$

$\sf{\implies} \: 2(20 + 16) \\ \\ \sf{\implies} \: 2(36) \\ \\\sf{\implies} \: 72$

Perimeter = 72 cm

$\rule{300}{1.5}$

Consider the side of the Square as y

Square's Perimeter = 72 cm

Side = y

★ $\textsf{\underline{\underline{Perimeter of Square - }}}$

$\boxed{\sf{Side \times 4}}$

$\sf{\implies} \: y \times 4 = 72 \\ \\ \sf{\implies} \: 4y = 72 \\ \\ \sf{\implies} \: y = \dfrac{72}{4} \\ \\ \sf{\implies} \: y = 18$

Side = 18 cm

$\therefore$ The Side of the Square is 18 cm.