a wire is bent into a rectangle of length 80cm and breadth 40cm.if the wire were straightened and then bent into a square,how much would its sides measure?
Answers
Answered by
1
Answer:
Step-by-step explanation:
Perimeter of rectangle=perimeter of square
2(l+b)=4a
2(80+40)=4a
2*120=4a
a=240/4
a=60cm
Answered by
0
Answer:
Step-by-step explanation:
Given
Length=80 cm
Breadth=40cm
Perimeter=2(l+b)
=2(80+40)
=2*120
=240
Primeterof rectangle =perimeter of square
240=4*side
240/4=side
60cm=side
Thus,side of square is 60cm
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