Question

A wire is bent into a right-angled triangle with sides in the ratio 3:4:5. The same wire is bent into an equilateral triangle. What is the ratio of their areas?
PLEASE ANSWER........

Answer 1

Answer:

3:2

Step-by-step explanation:

let sides be 3x , 4x and 5x.

perimeter is sum of all sides = 3x + 4x + 5x= 12x

equilateral triangle has all sides equal = 9x/3

so one side is 3x

now.

area of triangle = 1/2 base × height

so 6x^2

area of equilateral triangle = _/3 /4 × side

so aprox value is 4x^2

now ratio 6x^2/4x^2

answer 3 : 2