Question

A wire is bent into the form of a square of side 27.5cm. the wire is straightened and bent into the form of a circle. what will be the radius of the circle so formed

Answer 1

side of asquare=27.5
perimeter =4*27.5=110
then perimeter of circle=110
2πr=110
r=110/2π(π=22/7)
r=17.5cm

Answer 2

Radius of the formed circle is 17.51 cm

Step-by-step explanation:

A square has four equal sides. As the wire is bent into a square, all the sides will be 27.5 cm.  

Now, perimeter of square is the sum of all sides.

Perimeter of square = 27.5 + 27.5 + 27.5 + 27.5 = 110 cm

Now, the wire is straightened and bent into a circle. Here there is no loss in wire $\longrightarrow$ length of the wire is the same as before bending.

Circumference of the circle will be the same as perimeter of the square.

Circumference of the circle = 2Πr

Where, r is the radius of the circle.

$2 \pi r=110$

$2 \times 3.14 \times r=110$

$r=\frac{110}{6.28}=17.51$