Question

A wire is bent into the shape an equilateral triangle of side 12cm. Then it is stretched open and bent into the shape of a square , find the area of square.​

Answer 1

Answer:

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$81cm^{2}$

Step-by-step explanation:

Length of each side of equilateral triangle = 12cm

Perimeter of the equilateral triangle = 12×3 = 36cm

Perimeter of square = 36cm

Length of each side of square = 36/4 = 9cm

Area of square = $s^{2}$ = $9^{2}$ = $81cm^{2}$