a wire is bent into the shape of a square the area of the square is 49 CM square when the wire is bent into a semicircular shape find the radius of the semicircle
Answers
Answered by
236
Area of square = 49 cm
a^2 = 49
a= 7 cm
Side of square = 7 cm
Perimeter of square = Perimeter of semi circle
Perimeter of semi circle = 4* 7 = 28 cm
pi * r + 2r = 28
=> r (2+ pi) = 28
=> r (2+22/7) = 28
=> r (36/7) = 28
=> r = 28 * 7/36
=> r = 7*7/9
=> r = 49/9 cm
Radius of semi circle = 49/9
= 5.44 cm
a^2 = 49
a= 7 cm
Side of square = 7 cm
Perimeter of square = Perimeter of semi circle
Perimeter of semi circle = 4* 7 = 28 cm
pi * r + 2r = 28
=> r (2+ pi) = 28
=> r (2+22/7) = 28
=> r (36/7) = 28
=> r = 28 * 7/36
=> r = 7*7/9
=> r = 49/9 cm
Radius of semi circle = 49/9
= 5.44 cm
suzy5:
but it is in the case of protractor
Answered by
96
Given Area of square = 49cm.
We know that Area os square = a^2.
a^2 = 49
a = 7cm.
We know that perimeter of square = 4 * a
= 4 * 7
= 28cm.
Then,
the perimeter of semicircle = pir + 2r
pir + 2r = 28
r(pi + 2) = 28
r(22/7 + 2) = 28
36/7 * r = 28
36 r = 196
r = 196/36
r = 5.4cm.
We know that Area os square = a^2.
a^2 = 49
a = 7cm.
We know that perimeter of square = 4 * a
= 4 * 7
= 28cm.
Then,
the perimeter of semicircle = pir + 2r
pir + 2r = 28
r(pi + 2) = 28
r(22/7 + 2) = 28
36/7 * r = 28
36 r = 196
r = 196/36
r = 5.4cm.
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