Math, asked by akshay43186, 10 months ago

A wire is bent to form a square of side 22 cm .If the same wire is bent in the form of a circle, find the area enclosed by it.

Answers

Answered by wkchathura1974
10

Answer:

616cm²

Step-by-step explanation:

Length of the wire = 22×4 = 88cm

∴ the perimeter of the circle = 88cm

22÷7×d = 88cm

diameter = 88÷(22÷7) = 28cm

Area = 22÷7×radius²= 22÷7×14×14 = 616cm²

Answered by ƦαíηвσωStαƦ
3

Answer:

  • The area of the circle = 616cm²

Given:

  • A wire is bent to form a square of side 22 cm.
  • The same wire is bent in the form of a circle.

Need to find:

  • The area of the circle = ?

Solution:

Perimeter of square = 22 cm × 4

Perimeter of square = 88 cm

Let 'r' be the radius of the circle.

Same wire is bent in the form of a square and circle.

Therefore,

  • Circumference of the wire = Perimeter off the square

➜ 2πr = 88

➜ 2 × 22/7 × r = 88

➜ r = 88 × 7 / 2 × 22

➜ r = 14 cm

Formula used here:

  • Area of circle = πr²

Putting the values:

➪ Area of circle = 22/7 × 14 × 14 cm²

➪ Area of circle = 616 cm²

Therefore:

  • The area of the circle is 616cm².

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Similar questions