Math, asked by kamal69kishore69, 10 months ago

A
wire is bent to form a square of side 22cm if the same wire is bent in the form of circle find the area enclosed by it ?​

Answers

Answered by Anonymous
18

\boxed{Answer} = 616 {cm}^{2}

\large\underline\blue{Explanation}

\bold\green{Given}

  • Side of square(a) = 22cm

_________________________________

\overbrace{permeter\:of\:square = 4a=88cm}

\overbrace{length\:of\:wire = 88 cm}

\overbrace{Circumference\:of\:circle = 88cm}

(wire of length 88 cm is bent)

_________________________________

2\pi \:  r = 88 \\ \pi \: r = 44 \\ r =  \frac{44 \times 7}{22}   \\ r = 14cm

\bold{Radius\:of\:circle}= 14cm

\underline{Area\:of\:circle} = \pi{r}^{2}

 =  \frac{22}{7}  \times 14 \times 14 \\  = 22 \times 28 \\  = 616 {cm}^{2}

\bold\pink{Area\:of\:circle} = 616{cm}^{2}

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