Question

A wire is bent to form a square of side 44 cm. If the same wire is bent in the form of circle. Find the area enclosed by it​

Answer 1

Answer:

2464 cm²

Step-by-step explanation:

side of the square = 44 cm

the perimeter of square = 4 × s = 4 × 44 = 176 cm

the circumference of circle is equal to the perimeter of square as the same wire is bent to form the circle.

2πr = 176 cm

$2 \times \frac{22}{7} \times r = 176 \\ r = 176 \times \frac{7}{22} \times \frac{1}{2} \\ r = \frac{176 \times 7}{44} \\ r = 4 \times 7 \\ r = 28$

the radius of circle = 28 cm

area of circle = πr²

$= \frac{22}{7} \times {(28)}^{2} \\ = \frac{22}{7} \times 28 \times 28 \\ = 22 \times 28 \times 4 \\ = 2464 {cm}^{2}$

Hope you get your answer