a wire is bent to form a square of side 8 cm if this wire is reshaped to form a rectangle of length 10 cm find the a) perimeter of the rectangle (b) breadth of rectangle (c) area of the rectangle
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Step-by-step explanation:
here you go...
GIVEN-
Side of square =8 cm
Perimeter of square =32 m
Lenth of rectangle =10 cm
SOLUTION-
Therefore,
2(l+b)=32
10+b=16
b=6
Therefore, breadth = 6m
Now, area of square = side×side=8×8=64 cm2
Area of rectangle = length×breadth=10×6=60 cm2
CONCLUSION-
Therefore, square encloses more area.
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