Math, asked by yadavbhulaiprasad1, 3 days ago

A wire is bent to form a square with side 77 cm. Same wire rebent to form a circle. Find the radius of the circle​

Answers

Answered by ajajit9217
0

Answer:

The radius of the circle is 49 cm.

Step-by-step explanation:

Given:

Length of the side of the square = 77 cm.

Length of the wire used to form a square = perimeter pf square

As we know,

Perimeter of square = 4 × length of one side of square

                                  = 4 × 77 =308 cm.

Same wire is bent to form a circle.

Length of the wire = circumference of the circle = 308 cm.

Circumference of the circle = 2\pir              (where r is the radius of the circle)

                           308 = 2× (22/7) × r        (value of \pi = 22/7)

                         ( 308 × 7) / (2×22) = r

                              2156 / 44 = r

                                       r = 49 cm.

               

Answered by preeti353615
0

Answer:

A wire is bent to form a square with side of 77 cm. Same wire rebent to form a circle. The radius of the circle​ is 44 cm.

Step-by-step explanation:

Given: Side of square = 77 cm

Find: the radius of the circle​.

Step :

The perimeter of square = length of wire  

⇒ length of wire  = 4×  77 = 308 cm

Now, a circumference of circle = length of wire

⇒2πr = 308cm

⇒ 2 × 22/7 × r = 308

⇒ 44/7 × r = 308

⇒ r= 308 × 7/44

⇒  r​ = 7×7

r = 49  cm

Radius of circle =49 cm

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