Question

A wire is bent to form a triangle. If the lenght of the sides of the triangle are 3x^2 - 4x cm, 2x^2 - 4cm and 6x^2 + 2cm, find the length of the wire? ​

Answer 1

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To find length of wire:-means perimeter of the triangle formed by bending the wire.

Perimeter of ∆=Sum of all sides

P=(4x-2)+(7x-4)+(6x+2)

P=4x-2+7x-4+6x+2

P=10x+7x-4

P=17x-4

{\bf{\blue{Perimeter=17x-4}}}

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#Bebrainly☺️

Answer 2

Step-by-step explanation:

perimeter of ∆ = side + side + side

= (3x²+4x)+(2x²+4)+(6x+2)

= x(3x-4)+2(x²+2)+2(3x+1)

=(x+2+2) [(3x+4)(x²+2)(3x+1)] (ANS)