Question

A wire is bent to form a triangle. if the length of the side of the triangle are 3x²+4x cm,2x²+4 cm and 6x+2 cm find the length of wire

Answer 1

Answer:

(x+4) [(3x+4)(x²+2)(3x+1)]

BECAUSE:-

length of wire means perimeter.

perimeter of ∆ = side + side + side

= (3x²+4x)+(2x²+4)+(6x+2)

= x(3x-4)+2(x²+2)+2(3x+1)

=(x+2+2) [(3x+4)(x²+2)(3x+1)]

Answer 2

Answer:

5x sq + 2x -2 this is my answer