Question

a wire is bent to form a triangle , if the length of the sides of triangle are 4x-2 , 7x-4 and 6x+2 , find the length of the wire

Answer 1

Answer:

Step-by-step explanation:

the length of the wire is equal to the perimeter of the triangle namely

4x - 2 + 7x - 4 + 6x + 2 = 17x - 4.

Answer 2

${\pink{\bf{Hola!!}}}$

To find length of wire:-means perimeter of the triangle formed by bending the wire.

Perimeter of ∆=Sum of all sides

P=(4x-2)+(7x-4)+(6x+2)

P=4x-2+7x-4+6x+2

P=10x+7x-4

P=17x-4

${\bf{\blue{Perimeter=17x-4}}}$

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