A wire is cut in to 4 pieces, which are put together by sides to obtain one conductor. if the original resistance of wire was r, the resistance of the bundle will be.
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Hey there,
We know that R = I
So, when the wire is cut into four equal parts, the resistance of each part is 1/4th of the original substance.
Hence,
R1 = R/4, R2 = R/4,
R3 = R/4, and R4 = R.4,
(b) When these 4 parts are joined in parallel, we get
1/R' = 1/R1 + 1/R2 + 1/R3 + 1/R4
1/R' = 4/R + 4/R + 4/R + 4/R = 16/R
R' = R/16
The joint resistance is now 1/16th part of the original resistance.
Hope this helps!
We know that R = I
So, when the wire is cut into four equal parts, the resistance of each part is 1/4th of the original substance.
Hence,
R1 = R/4, R2 = R/4,
R3 = R/4, and R4 = R.4,
(b) When these 4 parts are joined in parallel, we get
1/R' = 1/R1 + 1/R2 + 1/R3 + 1/R4
1/R' = 4/R + 4/R + 4/R + 4/R = 16/R
R' = R/16
The joint resistance is now 1/16th part of the original resistance.
Hope this helps!
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