Math, asked by lamboriamahil, 8 months ago

A wire is cut into several small pieces. Each of the small pieces is bent into a square of side 2 cm. If the
total area of the small squares is 28 square cm. What was the original length of the wire ?​

Answers

Answered by divitv2007
18

Answer:

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Step-by-step explanation:

area of one square=2*2=4cm

number of squares = total area/individual area = 28/4= 7 squares

now. perimeter of each square = 2*4=8cm

total length of wires = 8cm *7=56cm

Answered by anushkadanekar
18

Answer: 56 cm

Step-by-step explanation:

Each square has side 2 cm, so has area 4 cm².

The total area of the squares is 28 cm², so there are 28 / 4 = 7 squares.

Each square uses 4 × 2 cm = 8 cm of wire for its perimeter.

So the length of wire is 7 × 8 cm = 56 cm.

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