Math, asked by kabeermandil23, 3 months ago

. A wire is cut into several small pieces each of the small piece is bent into a square of

side 2 cm. if the total area of the small square is 28 sq. cm. what was the original

length of the wire?​

Answers

Answered by glory4hell99vlo
4

Answer:

56 cm

Step-by-step explanation:

Length of one piece = Perimeter of the square =4×2 cm=8 cm

Let the number of pieces be n

We have given, total area of n square =28 cm2

⇒n×(side)2=28

⇒n×(2)2=28

⇒n=428=7

The original length of the wire

= Number of pieces × length of one piece

=7×8 cm=56 cm.

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