Question

a wire is cut into several small pieces each of these small pieces is bent into the square of side 8 cm if the total area of the small squares is 28 square centimetre what was the original length of the wire?​

Answer 1

Answer:

Each square has side 2 cm, so has area 4 cm². The total area of the squares is 28 cm², so there are 28 / 4 = 7 squares. Each square uses 4 × 2 cm = 8 cm of wire for its perimeter. So the length of wire is 7 × 8 cm = 56 cm.

Step-by-step explanation:

Length of one piece = Perimeter of the square =4×2 cm=8 cm

Let the number of pieces be n

We have given, total area of n square =28 cm²

⇒n×(side)² =28

⇒n×(2)²=28

⇒n= 28. =7

4

The original length of the wire

= Number of pieces × length of one piece

=7×8 cm=56 cm.

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Answer 2

$\: \huge\sf\underline \red{\underline{Answer:-}}$

Side Of A Square of a Small Pieces of wire

$\: = 2cm$

Perimeter of 1 square

$= 8cm$

And,. Area Of 1 square

$= 2 \times 2 \: cm² \: = \: 4 \: cm²$

Total Area Of All Small Squares

$= 28 \: cm²$

$\: </p><p>∴ \: number \: of \: squares \: = \:$

$total \: area \:$

$__________$

$\: Area \: \\ Of \\ 1 \\ square$

28cm²

_______

4cm²

$= 7$

Total Length Of Wire =

No. Of Squares × Perimeter Of 1 square

$= 7 \times 8cm \: = 56cm$

Hence, original length of the wire is

$56cm$