Math, asked by hasinivadivelan, 9 months ago

A wire is cut into two pieces measuring 4 3/20m[ mixed fraction] and 1/40m. What is the original length of the wire?

Answers

Answered by kanaklatavermadelhi

1

Answer:

Original length of wire = Sum of length of both wires

= 83/20 + 1/40

= (166+1)/40

= 167/40

= 4 7/40 [mixed fraction]

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