Physics, asked by umeshlaishram2020, 3 months ago

a wire is cut to half of its original lenght how would ot affect the elongation under a given load and how does it affect the max load of it can support without exceeding the elastic limit

Answers

Answered by Reeyan777
10

When a wire is loaded with a weight more than its elastic limit, the strain on the wire increases very fast. When the stress reaches the peak value, it is called breaking stress. The force that causes the wire to break is called breaking force.

The breaking force is directly proportional to the cross-sectional area of the wire and not its length. Similarly, breaking stress is dependent only on the material of the wire and not its size.

Thus, when an elastic wire is cut into half, there is no effect on the maximum load it can support.


umeshlaishram2020: thank you very much for your answer
Reeyan777: pls make me a brainlist pls I need it
Answered by steffiaspinno
2

When a wire is loaded with a weight greater than its elastic limit, the strain on the wire rapidly increases. Breaking stress occurs when the tension reaches its maximum magnitude. Breaking force is the force that causes the wire to break.

Explanation- The breaking force is related to the wire's cross-sectional area rather than its length. Similarly, breaking stress is determined only by the wire's composition rather than its size.

As a result, cutting an elastic wire in half has no effect on the maximum load it can support.

Hooke's Law establishes a link between the stress applied to a body and the resulting strain. F represents the force on a cable or wire, A represents its cross-sectional area, and L represents its original length.

where e denotes the extent

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