Question

A wire is given material having length are of cross section a has a of 4 ohm what would be the resistant of another wire of since material length 1/2 and area of cross section

Answer 1

We know that the resistance is P(rho) l/a. We can ignore P over here because the material is same in both cases. Now, R=l/a. 4=l/a. In the second case, they are asking resistance if the area is double and length is halved. So, R=l/2 whole divided by 2a.We get R=l/4a. But we l/a=4. So, 4/4=1 and so the answer is 1 ohm.