a wire is in a shape of rectangular whose length is 52 cm and breadth is 44 centimetre. if the same wire is bent into the shape of square. find the length of the side of a square. which cover more area rectangle or square?
Answers
Answered by
5
Answer:
Step-by-step explanation:
Area of rectangle = 52 cm x 44 cm = 2288 sq.cm
let length of square = a cm.
Area of square = a cm x a cm = a sq. cm.
since same wire used hence ,
Area of square = Area of rectangle
a x a = 2288
therefore,
a = 47.83 cm.
nikks72:
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Answered by
4
Answer:
the length of the side of the square is 48 centimeter. area of the square is greater than the area of the rectangle.
Step-by-step explanation:
perimeter of the rectangle wire =2×(52+44)
= 192 cm
one side of the square = 192÷4
= 48 cm
area of the rectangle = 52×44
= 2288 sq.cm
area of the square = 48×48
= 2304 sq.cm
bt in book answer is 48
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