Question

A wire is in length of a square of perimeter 64 cm . A rectangle is formed with this wire such that its length is 20 cm. Then the area of the rectangle is _____​

Answer 1

Answer: Perimeter of square = 4*side

So side of square =

64= 4*side

Side = 64/4=16cm

Perimeter means total length

So it will be same in case of rectangle

64= 2(l+b)

=2(20+b)

=40+2b

64-40=2b

24 =2b

b= 12

Area of rectangle=

l*b

=20*12

=240cm²

The perimeter of square = Perimeter of rectangle

64 = 2(l+b)

64 = 2(20+b)

b = 12 cm

Area of rectangle = l×b

= 20 × 12

=240 cm^2

hope this helped you,

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Step-by-step explanation:

Answer 2

Answer :

Area of rectangle = 120 cm²

Formulae used :

• Perimeter of rectangle = 2(l + b)

• Area of rectangle = l × b

Solution :

Given,

Perimeter of square = 64 cm

Length of rectangle, l = 20 cm

Perimeter of rectangle will also be 64 cm.

↣ 2(l + b) = 64

2(20 + b) = 64

20 + b = 32

b = 32 - 20

⇝ b = 12

∴ Area of triangle = l × b = 20 × 12 = 240 cm²

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