A wire is in shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side?
Also find which shape encloses more area
Answers
Answer:
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According to the question,
Perimeter of square=Perimeter of rectangle
⇒4× side=2(length+breadth)
⇒4×side=2(40+22)
⇒4×side=2×62
⇒ side= 2×62/4
=31cm
Thus, the side of the square is 31cm.
Now, Area of rectangle=length×breadth=40×22=880cm ²
And Area of square=side×side=31×31=961cm ²
Therefore, on comparing, the area of square is greater than that of rectangle.
Answer:
side's value will be 31
abd it will cover more area.
Step-by-step explanation:
if the length of the wire is 40cm
and breadth is 22cm
then the perimeter will be 2(22+40)cm
= 2(62)cm
=124cm
now if we bent the wire in a square shape, then
let's consider the each of its side will be x cm
then it's perimeter will be 4x cm
so
4x=124
x= (124/4)
x= 31
now
the rectangular shape will cover the area (22×40)cm²
=880cm²
and then area of the square will be (31×31)cm²= 961cm²