Question

A wire is in shape of a square of side 12 cm. It is again bent into a rectangle of length 15 cm. Find its .breadth. Which encloses more area and how much more?​

Answer 1

Step-by-step explanation:

A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 12 cm, find its breadth. Which figure encloses more area and by how much?

Let a be the side of a square, l be the length and b be the breadth of rectangle.

As length of wire is constant, perimeter of both shapes would be same,

⇒4a=2(l+b)

⇒40=2(12+b)

⇒b=18 cm

Area of square=a

2

=10

2

=100cm

2

Area of rectangle=lb=12×18=216cm

2

⇒ Area of rectangle is greater by 116cm

2

.