Math, asked by vaibhavprasundtg, 2 days ago

A wire is in the form of a circle of radius 21 m. It is now bent to form a square. Find its side.

Answers

Answered by crankybirds31
1

Step-by-step explanation:

"Circumference of circle = Perimeter of a rectangle = 2πr

= 2 × 22/7 × 21

= 132 m

Perimeter of a rectangle = 2(l + b)

132 = 2(l + b)

36 + b = 66

b = 66 - 36 = 30 m

∴ Area of the rectangle = l × b = 36 × 30

= 1080 m2"

Answered by harishsathya420
1

Answer:

33 cm

Step-by-step explanation:

THE SQUARE IS MADE FROM THE CIRCLE

SO IT HAS THE SAME PERIMETER OF THAT OF THE CIRCLE

CIRCUMFERENCE OF CIRCLE=PERIMETER OF SQUARE

CIRCUMFERENCE=2πr

=2×22/7×21

=132

THEREFORE THE PERIMETER OF SQUARE IS ALSO 132 cm

NOW TO FIND THE SIDE

PERIMETER OF SAUARE=4×SIDE

132=4×S

S=132/4

S=33 cm

THEREFORE THE SIDE OF THE SAUARE IS 33cm

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