Question

A wire is in the form of a circle of radius 21cm. It is bent into an equilateral triangle. Find the side of the triangle. (Take π =22\7)

Answer 1

Answer:

44cm

Step-by-step explanation:

Circumference of circle = 2$\pi$r=2*22/7* 21=132cm

now, sum of sides of equilatel triangle = 132cm

so side of equilater triangle = 132/3= 44cm

Answer 2

The side of the triangle is 44 cm

Step-by-step explanation:

A wire is in the form of a circle of radius 21cm.

Circumference of circle =$2 \pi r = 2 \times \frac{22}{7} \times 21= 132 cm$

Length of wire = 132 cm

Let the side of equilateral triangle be x

Perimeter of equilateral triangle = $3 \times Side = 3x$

We are given that the wire is bent into equilateral triangle

So, Length of wire will remain same

So, 3x=132

x=44

Hence the side of the triangle is 44 cm

#Learn more:

A wire is bent in the form of circle of diameter 84 cm is again bent in the form of an equilateral triangle. Find the length of side of the triangle. (Take π = 22/7)

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