Question

A wire is in the form of a circle of radius 21cm. It is now bent in the form of a equilateral triangle. Find
the sides of a triangle.
Ans:​

Answer 1

Answer :

• The sides of a triangle is 44cm

Given :

• A wire is in the form of a circle of radius 21cm

To find :

• sides of triangle

Solution :

Given that, a wire is in the form of a circle of radius is 21cm and its bent in the form of equilateral triangle so, length of wire will be remain same . so we have to find the sides of triangle

As we know that :

• circumference of circle = 2πr = 2 × 22/7 × 21 = 132cm

Then,

• length of wire is 132 cm

• Let the side of equilateral triangle be x
• Perimeter of equilateral triangle be 3x because 3 × side = 3x

According to Question ,

length of wire will be remain same

so,

● 3x = 132

● x = 132/3

● x = 44cm

Hence,the sides of triangle is 44cm

Answer 2

Answer:

Answer :

The sides of a triangle is 44cm

Given :

A wire is in the form of a circle of radius 21cm

To find :

sides of triangle

Solution :

Given that, a wire is in the form of a circle of radius is 21cm and its bent in the form of equilateral triangle so, length of wire will be remain same . so we have to find the sides of triangle

As we know that :

circumference of circle = 2πr = 2 × 22/7 × 21 = 132cm

Then,

length of wire is 132 cm

Let the side of equilateral triangle be x

Perimeter of equilateral triangle be 3x because 3 × side = 3x

According to Question ,

length of wire will be remain same

so,

● 3x = 132

● x = 132/3

● x = 44cm

Hence,the sides of triangle is 44cm

Step-by-step explanation:

Hope this answer will help you.