Question

a wire is in the form of a circle of radius 42 cm.it is bent into a square . determine the area of the square and compare the areas of the regions enclosed in the two cases ( use π=22/7)? please it's urgent? please show step by step ok? please

Answer 1

Radius of Circle = 42 cm

Circumference of circle = length of wire =
$2 \times \pi \times r \\ \\ = 2 \times \frac{22}{7} \times 42 \\ \\ = 44 \times 6 \\ \\ = 264 \: cm$
So, the square thus formed with 264 cm length wire,has one side

= 264/4

= 66 cm

Area of square =
${side}^{2} \\ \\ = 66 \times 66 \\ \\ = 4356 \: {cm}^{2}$

Area of circle =
$\pi \times {r}^{2} \\ \\ = \frac{22}{7} \times 42 \times 42 \\ \\ = 22 \times 6 \times 42 \\ \\ = 5544 \: {cm}^{2}$

Area enclosed by wire when forming a circle is 5544 cm ^2

while 4356 cm ^2 on forming a square,thus area of circle is larger than square by 1188 cm^2.

Hope you understand it .

Answer 2

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"