A wire is in the form of a circle of radius 42 cm. It is bent into square . Find the side of the square. (Take " pii " 22/7).
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Answered by
15
Given that, a wire of radius 42cm is bent into a square.
So,it's perimeter is 2×22/7×42=264cm
As it is bent into a square the perimeters are equal.So,
4s=264
s=264/4
s=66cm
Therefore, the side of the square is 66cm
So,it's perimeter is 2×22/7×42=264cm
As it is bent into a square the perimeters are equal.So,
4s=264
s=264/4
s=66cm
Therefore, the side of the square is 66cm
Answered by
9
The wire is in the form of circle whose radius is 42cm
We can find the circumference of the circle
= 2πr
= 2 × 22/7 × 42
= 264 cm
So,
according to the question,
The same wire is bent into a square
So the circumference of the circle is equal to the perimeter of the square
➡️ 264 = 4 × side
➡️ 264 ÷ 4 = side
➡️ 66 = side
Therefore,
the side of the square is 66cm
We can find the circumference of the circle
= 2πr
= 2 × 22/7 × 42
= 264 cm
So,
according to the question,
The same wire is bent into a square
So the circumference of the circle is equal to the perimeter of the square
➡️ 264 = 4 × side
➡️ 264 ÷ 4 = side
➡️ 66 = side
Therefore,
the side of the square is 66cm
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