a wire is in the form of a circle with radius 42cm it is bent into a square find the side of a square
Answers
Answered by
123
radius=42
perimeter=2πr=264 cm
then perimeter of square=264
4s=264
s=66
side=66cm
perimeter=2πr=264 cm
then perimeter of square=264
4s=264
s=66
side=66cm
Answered by
65
hello users
solution
Given that
wire in the form of a circle with radius 42 cm bent to form a square.
=> perimeter of circle = perimeter of square
we know that
perimeter of circle = 2πr
and
perimeter of square = 4 a
where, r is the radius and a is the side of square.
=> perimeter of circle = 2πr
= 2 * 22/7 * 42
= 44 * 6
= 4* 66
Now,
According to question
perimeter of square = 4a = 4 * 66
=> a = 66 cm Answer
# hope it helps :)
solution
Given that
wire in the form of a circle with radius 42 cm bent to form a square.
=> perimeter of circle = perimeter of square
we know that
perimeter of circle = 2πr
and
perimeter of square = 4 a
where, r is the radius and a is the side of square.
=> perimeter of circle = 2πr
= 2 * 22/7 * 42
= 44 * 6
= 4* 66
Now,
According to question
perimeter of square = 4a = 4 * 66
=> a = 66 cm Answer
# hope it helps :)
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