Question

A wire is in the form of a rectangle 8.9 cm long and 5.4 cm broad. It is reshaped and bent in the form of a circle find the radius of Circle.​

Answer 1

• A piece of wire in the from of a rectangle 8.9 cm long and 5.4 cm broad. A piece of wire in the from of a rectangle is reshaped and bent into the from of a circle. Therefore, the radius of the circle is 4.55 cm

Answer 2

$\huge{\mathcal{\underline\pink{Question}}}$

A wire is in the form of a rectangle 8.9 cm long and 5.4 cm broad. It is reshaped and bent in the form of a circle find the radius of Circle.

$\huge{\underline{\mathtt{\red{A} \pink{N} \green{S} \blue{W} \purple{E} \orange{R}}}}$

$\huge\boxed{\blue{Given :}}$

➣ First a wire is bent in the shape of a rectangle and After it is rebent to form a circle.

➣ Length of Rectangle = 8.9 m

➣ Breadth of Rectangle = 5.4 m

$\huge\boxed{\red{To \: Find :}}$

➣ The Radius of Circle

$\huge\boxed{\pink {Solution :}}$

➪ Perimeter of Rectangle = 2( length + breadth)

⇒ Perimeter of Rectangle = 2(8.9+5.4)

⇒ Perimeter of Rectangle = 2 × 14.3

⇒ Perimeter of Rectangle = 28.6 cm

$\:$

➦ Perimeter of Rectangle = Perimeter of Circle = 28.6 cm

$\:$

➪ Perimeter of Circle = 2πr

⇒28.6 cm = 2πr

$⇒ \: r \: = \frac{28.6}{2\pi}$

$⇒ \: r \: = \frac{28.6 \times 7}{2 \times 22}$

⇒ r = 4.55 cm

➦ So, the radius of the Circle is 4.55 cm..