Question

a wire is in the form of a square, encloses an area of 1936 cm square. if the same wire is rebent into circle. find the area enclosed

Answer 1

Given , area of square = 1936 cm. sq.
we know that area of square = a²
so , a²=1936 cm. sq.
a = √1936
a = 44cm
as per the problem, same wire is used to rebent into a circle..
it means , perimeter of square is equal to (=) circumference of circle..
so, perimeter of circle = 4a
4×44=88cm        ( we got a=44)
circumference of circle = 88cm
But, we know that, circumference of circle = 2πr
so,   2πr = 88
2×22÷7×r = 88
r = 88×7÷2×22
r=14cm
Area of circle = πr²
22÷7×14²
616 sq. cm.
therefore,area of rebent circle is 616 cm²

Answer 2

Answer:

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Step-by-step explanation:

Given , area of square = 1936 cm. sq.

we know that area of square = a²

so , a²=1936 cm. sq.

a = √1936

a = 44cm

as per the problem, same wire is used to rebent into a circle..

it means , perimeter of square is equal to (=) circumference of circle.

so, perimeter of circle = 4a

4×44=88cm        ( we got a=44)

circumference of circle = 88cm

But, we know that, circumference of circle = 2πr

so,   2πr = 88

2×22÷7×r = 88

r = 88×7÷2×22

r=14cm

Area of circle = πr²

22÷7×14²

616 sq. cm.

therefore,area of rebent circle is 616 cm²