Question

A wire is in the form of circle of radius 35 m it is now bent in the form of a equilateral triangle find the sides of triangle​

Answer 1

length of wire = circumference of circle

= 2πr

= 2X22X35/7

= 220m

each side of triangle = a

length of wire = perimeter of triangle

a+a+a = 220

a = 220/3

a = 73.33m

Answer 2

The sides of triangle​ is 73.3 m

Step-by-step explanation:

Radius of circle of wire = 35 m

Perimeter of circular wire =$2 \pi r = 2 \times \frac{22}{7} \times 35 = 220 m$

Perimeter of equilateral triangle = $3 \times Side$

So,$3 \times Side =220$

$Side = \frac{220}{3}$

Side = 73.3 m

Hence the sides of triangle​ is 73.3 m

#Learn more:

A piece of wire is bent in the shape of equilateral triangle of side 4.4 cm.if this wire is bent to form a circle find the radius and area of the circle

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